7.44) f(x)=a∗x2+bx+c f(0)=5⇒c=5 f(20)=0 f(−20)=0 Nlöse f(x)=−80x1+5 f′(x)=−40x1 S=2∗∫0201+40x2dx≈41.6m 7.45) Hineweis: cosh2x−sinh2x=1 cosh2x=1+sinh2x