diodenampelschaltung-oda-so-ein-kram-oida

$U_q=U_v+U_F$ Typ. LED: U_{F}=1.6 \dots 2.5V$$$$I_{Fmax}=mA Rpi: GPIO-POrt 3,3V 10mA Ziel: 10mA max LED → 0.6V/2.2mA $U=R\ast I=\text{ohm}\ast 2.2mA=R=\frac{2,7V}{2,2mA}\approx 1,2k\text{ohm}$

$I=16ma\to U_F\approx 0.75V$ $R_V\Rightarrow U_V=2,55V$ $R_V=\frac{2.55V}{16mA}\approx 160\text{ohm}$